The formula
E = ½ × C × V² (capacitor) ; E = ½ × L × I² (inductor) ; Q = C × V
- E
- stored energy (joules)
- C
- capacitance (farads)
- V
- voltage across the capacitor (volts)
- L
- inductance (henries)
- I
- current through the inductor (amperes)
Worked example
A 1000 µF capacitor charged to 25 V, and a 10 mH inductor carrying 2 A.
- Capacitor: E = ½ × 1000×10⁻⁶ × 25² = ½ × 0.001 × 625
- Charge held: Q = 0.001 × 25 = 25 mC
- Inductor: E = ½ × 0.01 × 2² = ½ × 0.01 × 4
0.3125 J in the capacitor, 0.02 J in the inductor.
Where you'll use it
Sizing smoothing and hold-up capacitors, flash circuits, and switching supplies. The inductor formula is also the safety one: interrupting inductor current forces that energy out as a voltage spike, which is why relay coils need flyback diodes.