The formula
η = P_out / (P_out + P_iron + P_copper) ; Regulation % = (V_no-load − V_full-load) / V_full-load × 100
- η
- efficiency (per cent)
- P_out
- output power = kVA × load fraction × power factor
- P_iron
- core loss — constant at all loads (watts)
- P_copper
- winding loss — scales with load fraction squared (watts)
Worked example
A 100 kVA transformer at full load, pf 0.8, with 1 kW iron loss and 1.5 kW full-load copper loss.
- Output: P_out = 100 × 0.8 = 80 kW
- Total losses: 1 + 1.5 = 2.5 kW
- η = 80 / (80 + 2.5) = 80 / 82.5
η = 96.97 %. Maximum efficiency would occur at √(1/1.5) = 81.6 % of full load.
Where you'll use it
Machine design papers and energy audits. The condition for maximum efficiency — copper loss equal to iron loss — is one of the most reliably examined results in the subject.