The formula
I = kW × 1000 / (√3 × V × η × cos φ) [three phase]
- kW
- nameplate output power (hp × 0.7355 for metric horsepower)
- V
- line voltage
- η
- full-load efficiency, as a fraction
- cos φ
- full-load power factor
- √3
- present for three phase, absent for single phase
Worked example
A 7.5 kW three-phase motor on 415 V, 88 % efficient at 0.85 power factor.
- Input power = 7.5 / 0.88 = 8.52 kW
- Input apparent power = 8.52 / 0.85 = 10.03 kVA
- I = 7500 / (1.732 × 415 × 0.88 × 0.85)
- I = 13.95 A
- Direct-on-line starting draws roughly 6 × that — about 84 A for a few seconds
13.95 A full load, about 84 A while starting.
Where you'll use it
Sizing the cable, the breaker and the starter for a motor circuit, and checking a nameplate current that looks wrong. The starting figure is why motor circuits use a C or D curve breaker: a B curve would trip every time the motor started.